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Suppose that TCP's current estimated values for the round trip time (estimatedRTT) and deviation in the RTT (DevRTT) are 250 msec and 38 msec, respectively (see Section 3.5.3 for a discussion of these variables). Suppose that the next three measured values of the RTT are 280 msec, 200 msec, and 340 msec respectively. <image 1> Compute TCP's new value of DevRTT, estimatedRTT, and the TCP timeout value after each of these three measured RTT values is obtained. Use the values of $\alpha$ = 0.125, and $\beta$ = 0.25. Round your answers to two decimal places after leading zeros. What is the estimatedRTT after the first RTT?	Google: Gemini Pro Vision 1.0 mmmu / Computer_SciencePublic After the first RTT, the estimatedRTT is: 0.125 * (280 - 250) + 0.875 * 250 = 253.125 msec The DevRTT is: 0.25 * \|280 - 253.125\| + 0.75 * 38 = 41.875 msec The TCP Timeout value is: 253.125 + 4 * 41.875 = 415.5 msec After the second RTT, the estimatedRTT is: 0.125 * (200 - 253.125) + 0.875 * 253.125 = 239.062 msec The DevRTT is: 0.25 * \|200 - 239.062\| + 0.75 * 41.875 = 33.438 msec The TCP Timeout value is: 239.062 + 4 * 33.438 = 373.438 msec After the third RTT, the estimatedRTT is: 0.125 * (340 - 239.062) + 0.875 * 239.062 = 260.938 msec The DevRTT is: 0.25 * \|340 - 260.938\| + 0.75 * 33.438 = 44.062 msec The TCP Timeout value is: 260.938 + 4 * 44.062 = 433.938 msec Expected Answer: 253.75 Difficulty: Hard Subfield: Computer Network

Input

Output

Suppose that TCP's current estimated values for the round trip time (estimatedRTT) and deviation in the RTT (DevRTT) are 250 msec and 38 msec, respectively (see Section 3.5.3 for a discussion of these variables). Suppose that the next three measured values of the RTT are 280 msec, 200 msec, and 340 msec respectively. <image 1> Compute TCP's new value of DevRTT, estimatedRTT, and the TCP timeout value after each of these three measured RTT values is obtained. Use the values of $\alpha$ = 0.125, and $\beta$ = 0.25. Round your answers to two decimal places after leading zeros. What is the estimatedRTT after the first RTT?

Google: Gemini Pro Vision 1.0

mmmu / Computer_SciencePublic

After the first RTT, the estimatedRTT is: 0.125 * (280 - 250) + 0.875 * 250 = 253.125 msec

The DevRTT is: 0.25 * |280 - 253.125| + 0.75 * 38 = 41.875 msec

The TCP Timeout value is: 253.125 + 4 * 41.875 = 415.5 msec

After the second RTT, the estimatedRTT is: 0.125 * (200 - 253.125) + 0.875 * 253.125 = 239.062 msec

The DevRTT is: 0.25 * |200 - 239.062| + 0.75 * 41.875 = 33.438 msec

The TCP Timeout value is: 239.062 + 4 * 33.438 = 373.438 msec

After the third RTT, the estimatedRTT is: 0.125 * (340 - 239.062) + 0.875 * 239.062 = 260.938 msec

The DevRTT is: 0.25 * |340 - 260.938| + 0.75 * 33.438 = 44.062 msec

The TCP Timeout value is: 260.938 + 4 * 44.062 = 433.938 msec

Expected Answer: 253.75

Difficulty: Hard

Subfield: Computer Network

Input

Input ID: d35c65a5-b5a7-41f8-afa5-7371cbac5234
Created: February 13, 2024
Permission: Public