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Suppose that TCP's current estimated values for the round trip time (estimatedRTT) and deviation in the RTT (DevRTT) are 250 msec and 38 msec, respectively (see Section 3.5.3 for a discussion of these variables). Suppose that the next three measured values of the RTT are 280 msec, 200 msec, and 340 msec respectively. <image 1> Compute TCP's new value of DevRTT, estimatedRTT, and the TCP timeout value after each of these three measured RTT values is obtained. Use the values of α\alpha = 0.125, and β\beta = 0.25. Round your answers to two decimal places after leading zeros. What is the estimatedRTT after the first RTT?


Google: Gemini Pro Vision 1.0
mmmu / Computer_SciencePublic

After the first RTT, the estimatedRTT is: 0.125 * (280 - 250) + 0.875 * 250 = 253.125 msec

The DevRTT is: 0.25 * |280 - 253.125| + 0.75 * 38 = 41.875 msec

The TCP Timeout value is: 253.125 + 4 * 41.875 = 415.5 msec

After the second RTT, the estimatedRTT is: 0.125 * (200 - 253.125) + 0.875 * 253.125 = 239.062 msec

The DevRTT is: 0.25 * |200 - 239.062| + 0.75 * 41.875 = 33.438 msec

The TCP Timeout value is: 239.062 + 4 * 33.438 = 373.438 msec

After the third RTT, the estimatedRTT is: 0.125 * (340 - 239.062) + 0.875 * 239.062 = 260.938 msec

The DevRTT is: 0.25 * |340 - 260.938| + 0.75 * 33.438 = 44.062 msec

The TCP Timeout value is: 260.938 + 4 * 44.062 = 433.938 msec


Expected Answer: 253.75

Difficulty: Hard

Subfield: Computer Network

Evaluation

Evaluation ID
b7300686-2eb8-4841-bf93-dfc8a1d36c8f
Created
February 21, 2024
Raw Output
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        "content": " After the first RTT, the estimatedRTT is:\n0.125 * (280 - 250) + 0.875 * 250 = 253.125 msec\n\nThe DevRTT is:\n0.25 * |280 - 253.125| + 0.75 * 38 = 41.875 msec\n\nThe TCP Timeout value is:\n253.125 + 4 * 41.875 = 415.5 msec\n\nAfter the second RTT, the estimatedRTT is:\n0.125 * (200 - 253.125) + 0.875 * 253.125 = 239.062 msec\n\nThe DevRTT is:\n0.25 * |200 - 239.062| + 0.75 * 41.875 = 33.438 msec\n\nThe TCP Timeout value is:\n239.062 + 4 * 33.438 = 373.438 msec\n\nAfter the third RTT, the estimatedRTT is:\n0.125 * (340 - 239.062) + 0.875 * 239.062 = 260.938 msec\n\nThe DevRTT is:\n0.25 * |340 - 260.938| + 0.75 * 33.438 = 44.062 msec\n\nThe TCP Timeout value is:\n260.938 + 4 * 44.062 = 433.938 msec"
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