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Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 300 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 80 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 60 Mbps. <image 1> What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? Omit the unit of Mbps.	Nous: Hermes 2 Vision 7B (alpha) mmmu / Computer_SciencePublic For each client-to-server pair, given the division of the middle link's transmission rate equally, the end-end throughput in Mbps can be calculated as follows: End-end throughput = (RS/3) * (R/3) * 2 End-end throughput = 30060 2 End-end throughput = 1800 So, for each client-to-server pair, the maximum achievable end-end throughput is 1800 Mbps. Expected Answer: 60 Difficulty: Medium Subfield: Computer Network
Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 300 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 80 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 60 Mbps. <image 1> What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? Omit the unit of Mbps.	Google: Gemini Pro Vision 1.0 mmmu / Computer_SciencePublic 60 Expected Answer: 60 Difficulty: Medium Subfield: Computer Network

Input

Output

Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 300 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 80 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 60 Mbps. <image 1> What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? Omit the unit of Mbps.

Nous: Hermes 2 Vision 7B (alpha)

mmmu / Computer_SciencePublic

For each client-to-server pair, given the division of the middle link's transmission rate equally, the end-end throughput in Mbps can be calculated as follows:

End-end throughput = (RS/3) * (R/3) * 2 End-end throughput = 300*60 * 2 End-end throughput = 1800

So, for each client-to-server pair, the maximum achievable end-end throughput is 1800 Mbps.

Expected Answer: 60

Difficulty: Medium

Subfield: Computer Network

Google: Gemini Pro Vision 1.0

mmmu / Computer_SciencePublic

Expected Answer: 60

Difficulty: Medium

Subfield: Computer Network

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Input

Input ID: 53f47e2f-a3ca-4146-bde6-30fea7d304c7
Created: February 13, 2024
Permission: Public