Input | Output |
---|---|
![]() Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 300 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 80 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 60 Mbps. <image 1> What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? Omit the unit of Mbps. | For each client-to-server pair, given the division of the middle link's transmission rate equally, the end-end throughput in Mbps can be calculated as follows: End-end throughput = (RS/3) * (R/3) * 2 End-end throughput = 300*60 * 2 End-end throughput = 1800 So, for each client-to-server pair, the maximum achievable end-end throughput is 1800 Mbps. Expected Answer: 60 Difficulty: Medium Subfield: Computer Network |
{ "choices": [ { "message": { "role": "assistant", "content": "For each client-to-server pair, given the division of the middle link's transmission rate equally, the end-end throughput in Mbps can be calculated as follows:\n\nEnd-end throughput = (RS/3) * (R/3) * 2\nEnd-end throughput = 300*60 * 2\nEnd-end throughput = 1800\n\nSo, for each client-to-server pair, the maximum achievable end-end throughput is 1800 Mbps. " } } ], "model": "nousresearch/nous-hermes-2-vision-7b", "id": "gen-rVmit8jvMCLn0CEgt828I9Zsi7Ar", "object": "chat.completion", "created": 1708558331, "usage": { "prompt_tokens": 166, "completion_tokens": 127, "total_tokens": 293 } }