Input | Output |
|---|---|
 Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 300 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 80 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 60 Mbps. <image 1> What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? Omit the unit of Mbps. | For each client-to-server pair, given the division of the middle link's transmission rate equally, the end-end throughput in Mbps can be calculated as follows: End-end throughput = (RS/3) * (R/3) * 2 End-end throughput = 300*60 * 2 End-end throughput = 1800 So, for each client-to-server pair, the maximum achievable end-end throughput is 1800 Mbps. Difficulty: Medium Subfield: Computer Network |
Evaluation
- Evaluation ID
- 2a007503-f7ef-4f88-9570-6d192842de4a
- Created
- February 21, 2024
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