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Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 300 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 80 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 60 Mbps. <image 1> What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? Omit the unit of Mbps.


Nous: Hermes 2 Vision 7B (alpha)
mmmu / Computer_SciencePublic

For each client-to-server pair, given the division of the middle link's transmission rate equally, the end-end throughput in Mbps can be calculated as follows:

End-end throughput = (RS/3) * (R/3) * 2 End-end throughput = 300*60 * 2 End-end throughput = 1800

So, for each client-to-server pair, the maximum achievable end-end throughput is 1800 Mbps.


Expected Answer: 60

Difficulty: Medium

Subfield: Computer Network

Evaluation

Evaluation ID
2a007503-f7ef-4f88-9570-6d192842de4a
Created
February 21, 2024
Raw Output
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