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A valve in the cylinder shown in <image 1> has a cross-sectional area of 11 cm2 with a pressure of 735 kPa inside the cylinder and 99 kPa outside.How large a force is needed to open the valve?



(A) F=689.4N


(B) F=660.5N


(C) F=699.6N


(D) F=709.6N


Answer with the option's letter from the given choices directly. No punctuation.


A


Expected Answer: C

Difficulty: Hard

Subfield: Thermodynamics


Explanation: Force required to open the valve,$F_{net}=P_{in}\cdot A-P_{out}\cdot A$Where A is the area of valve,$A=11cm^{2}=11\cdot10^{-4}m^{2}$.So,$F_{net}=(735-99)\cdot(11\cdot10^{-4})$

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Input ID
267ee532-57d3-4b11-8a85-33e924c3d442
Created
February 15, 2024
Permission
Public