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A valve in the cylinder shown in <image 1> has a cross-sectional area of 11 cm2 with a pressure of 735 kPa inside the cylinder and 99 kPa outside.How large a force is needed to open the valve? (A) F=689.4N (B) F=660.5N (C) F=699.6N (D) F=709.6N Answer with the option's letter from the given choices directly. No punctuation.	Google: Gemini Pro Vision 1.0 mmmu / Energy_and_PowerPublic A Expected Answer: C Difficulty: Hard Subfield: Thermodynamics Explanation: Force required to open the valve,$F_{net}=P_{in}\cdot A-P_{out}\cdot A$Where A is the area of valve,$A=11cm^{2}=11\cdot10^{-4}m^{2}$.So,$F_{net}=(735-99)\cdot(11\cdot10^{-4})$